1596=6x^2+30x

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Solution for 1596=6x^2+30x equation:



1596=6x^2+30x
We move all terms to the left:
1596-(6x^2+30x)=0
We get rid of parentheses
-6x^2-30x+1596=0
a = -6; b = -30; c = +1596;
Δ = b2-4ac
Δ = -302-4·(-6)·1596
Δ = 39204
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{39204}=198$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-198}{2*-6}=\frac{-168}{-12} =+14 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+198}{2*-6}=\frac{228}{-12} =-19 $

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